The full logical solve of the hard Skyscrapers for September 8 to September 14, 2026, 8 × 8. 56 steps, 6 techniques, no guessing. Step through it, or jump to any step below.
From the left of row 6 you see just 1 building, so the tallest, 8, stands right at that edge. It hides all the others. That leaves the marked cell with one height: 8.
This takes 5 steps. The last two: The clue at the top of column 7 is 6, so 5 taller buildings must stand behind the first one. The cell next to that edge can be at most 3, the one after at most 4, and so on. The clue at the right of row 1 is 2. If the tallest building, 8, stood in the first cell from that edge, you would see fewer than 2. So 8 can’t go there. Now 8 fits in only one cell of row 1: the marked one.
From the right of row 3 you see just 1 building, so the tallest, 8, stands right at that edge. It hides all the others. That leaves the marked cell with one height: 8.
This takes 7 steps. The last two: The clue at the left of row 7 is 4, so 3 taller buildings must stand behind the first one. The cell next to that edge can be at most 5, the one after at most 6, and so on. The clue at the right of row 8 is 3. If the tallest building, 8, stood in the first 2 cells from that edge, you would see fewer than 3. So 8 can’t go there. Now 8 fits in only one cell of column 7: the marked one.
This takes 3 steps. The last two: Look along the line from the right of row 1. Only some orders of the heights still possible here show exactly 2 buildings, and that rules some heights out of the orange cells. Look along the line from the top of column 6. Only some orders of the heights still possible here show exactly 2 buildings, and that rules some heights out of the orange cells. That leaves the marked cell with one height: 8.
In row 8, 8 fits only in the marked cell.
In row 5, 8 fits only in the marked cell.
Look along the line from the top of column 5. Only some orders of the heights still possible here show exactly 2 buildings, and that rules some heights out of the orange cells. That leaves the marked cell with one height: 6.
That leaves the marked cell with one height: 7.
That leaves the marked cell with one height: 7.
In row 2, 7 fits only in the marked cell.
Look along the line from the top of column 7. Only some orders of the heights still possible here show exactly 6 buildings, and that rules some heights out of the orange cells. That leaves the marked cell with one height: 6.
That leaves the marked cell with one height: 7.
In column 2, 7 fits only in the marked cell.
In column 1, 7 fits only in the marked cell.
This takes 5 steps. The last two: Look along the line from the bottom of column 2. Only some orders of the heights still possible here show exactly 4 buildings, and none of them puts 1 in the orange cell. Look along the line from the left of row 4. Only some orders of the heights still possible here show exactly 3 buildings, and that rules some heights out of the orange cells. That leaves the marked cell with one height: 7.
In row 7, 7 fits only in the marked cell.
Look along the line from the top of column 3. Only some orders of the heights still possible here show exactly 4 buildings, and none of them puts 5 in the orange cell. Now 5 fits in only one cell of row 2: the marked one.
This takes 3 steps. The last two: Look along the line from the left of row 5. Only some orders of the heights still possible here show exactly 2 buildings, and that rules some heights out of the orange cells. Look along the line from the left of row 7. Only some orders of the heights still possible here show exactly 4 buildings, and that rules some heights out of the orange cells. That leaves the marked cell with one height: 6.
That leaves the marked cell with one height: 1.
In row 2, 6 fits only in the marked cell.
In row 5, 1 fits only in the marked cell.
Look along the line from the right of row 8. Only some orders of the heights still possible here show exactly 3 buildings, and that rules some heights out of the orange cells. That leaves the marked cell with one height: 5.
That leaves the marked cell with one height: 6.
In column 1, a few cells share just a few heights between them, so those heights can’t go in the orange cells. That leaves the marked cell with one height: 6.
In row 3, 6 fits only in the marked cell.
In row 6, 6 fits only in the marked cell.
Look along the line from the bottom of column 8. Only some orders of the heights still possible here show exactly 4 buildings, and none of them puts 2 in the orange cell. Now 2 fits in only one cell of row 7: the marked one.
In row 3, 2 fits only in the marked cell.
In row 4, 2 fits only in the marked cell.
In column 5, 1 fits only in the marked cell.
That leaves the marked cell with one height: 2.
That leaves the marked cell with one height: 3.
The marked cell’s row and column hold every height except 4, so it must be 4.
The marked cell’s row and column hold every height except 2, so it must be 2.
The marked cell’s row and column hold every height except 3, so it must be 3.
The marked cell’s row and column hold every height except 4, so it must be 4.
The marked cell’s row and column hold every height except 3, so it must be 3.
The marked cell’s row and column hold every height except 4, so it must be 4.
The marked cell’s row and column hold every height except 3, so it must be 3.
That leaves the marked cell with one height: 1.
The marked cell’s row and column hold every height except 5, so it must be 5.
The marked cell’s row and column hold every height except 4, so it must be 4.
The marked cell’s row and column hold every height except 3, so it must be 3.
The marked cell’s row and column hold every height except 2, so it must be 2.
The marked cell’s row and column hold every height except 1, so it must be 1.
The marked cell’s row and column hold every height except 4, so it must be 4.
The marked cell’s row and column hold every height except 5, so it must be 5.
The marked cell’s row and column hold every height except 5, so it must be 5.
The marked cell’s row and column hold every height except 1, so it must be 1.
The marked cell’s row and column hold every height except 4, so it must be 4.
The marked cell’s row and column hold every height except 3, so it must be 3.
The marked cell’s row and column hold every height except 4, so it must be 4.
The marked cell’s row and column hold every height except 3, so it must be 3.
The marked cell’s row and column hold every height except 2, so it must be 2.
The marked cell’s row and column hold every height except 4, so it must be 4.