The full logical solve of the hard Fillomino for September 29 to October 5, 2026, 10 × 10. 38 steps, 3 techniques, no guessing. Step through it, or jump to any step below.
This 3 has one cell and needs 2 more. Its only open side is r2c7, so that cell is 3.
This 4 has one cell and needs 3 more. Its only open side is r4c6, so that cell is 4.
This 5 has one cell and needs 4 more. Its only open side is r5c5, so that cell is 5.
Each other number either has no room to fit around r5c8 or would touch a region of its own size. Only 5 is left.
Each other number either has no room to fit around r8c5 or would touch a region of its own size. Only 4 is left.
Try each number that fits in r3c9. 3 and 9 each lead to a broken rule. So it is 8.
Try each number that fits in r4c9. A 9 leads to a broken rule: a region grows too big or runs out of room. So it is 8.
Try each number that fits in r6c7. 3 and 4 each lead to a broken rule. So it is 5.
Try each number that fits in r5c6. 1 and 3 each lead to a broken rule. So it is 4.
Try each number that fits in r6c6. 1, 3 and 5 each lead to a broken rule. So it is 4.
This 5 has 4 cells and needs 1 more. Its only open side is r7c8, so that cell is 5.
Try each number that fits in r2c6. 1 and 4 each lead to a broken rule. So it is 2.
Try each number that fits in r1c5. A 1 leads to a broken rule: a region grows too big or runs out of room. So it is 4.
Try each number that fits in r9c7. 1, 5 and 6 each lead to a broken rule. So it is 3.
This 5 has one cell and needs 4 more. The only open side it can grow through is r9c9, so that cell is 5.
This 9 needs 8 more cells, and exactly that many cells around it could join. So r4c10, r6c10, r6c9, r7c10, r7c9, r8c10, r8c9 and r8c8 are 9.
This 3 has 2 cells and needs 1 more. Its only open side is r9c6, so that cell is 3.
This 6 has one cell and needs 5 more. Its only open side is r10c5, so that cell is 6.
This 6 has 2 cells and needs 4 more. Its only open side is r10c4, so that cell is 6.
This 8 needs 5 more cells, and exactly that many cells around it could join. So r1c9, r2c8, r2c10, r1c8 and r1c10 are 8.
This 5 needs 2 more cells, and exactly that many cells around it could join. So r10c9 and r10c10 are 5.
Try each number that fits in r9c4. A 6 leads to a broken rule: a region grows too big or runs out of room. So it is 4.
This 6 has 3 cells and needs 3 more. Its only open side is r10c3, so that cell is 6.
This 6 has 4 cells and needs 2 more. Its only open side is r10c2, so that cell is 6.
Each other number either has no room to fit around r10c1 or would touch a region of its own size. Only 6 is left.
Each other number either has no room to fit around r9c2 or would touch a region of its own size. Only 8 is left.
This 8 needs 6 more cells, and exactly that many cells around it could join. So r7c2, r8c1, r7c1, r7c3, r6c1 and r7c4 are 8.
This 3 has 2 cells and needs 1 more. Its only open side is r6c5, so that cell is 3.
This 5 has 2 cells and needs 3 more. Its only open side is r4c5, so that cell is 5.
This 5 has 3 cells and needs 2 more. Its only open side is r3c5, so that cell is 5.
This 5 has 4 cells and needs 1 more. Its only open side is r3c4, so that cell is 5.
This 6 has one cell and needs 5 more. Its only open side is r4c3, so that cell is 6.
This 7 needs 6 more cells, and exactly that many cells around it could join. So r1c2, r2c3, r1c1, r1c3, r2c4 and r3c3 are 7.
This 4 has 3 cells and needs 1 more. Its only open side is r1c6, so that cell is 4.
This 4 has one cell and needs 3 more. Its only open side is r3c1, so that cell is 4.
This 4 has 2 cells and needs 2 more. Its only open side is r4c1, so that cell is 4.
This 6 has one cell and needs 5 more. Its only open side is r4c2, so that cell is 6.
This 6 has 5 cells and needs 1 more. Its only open side is r5c2, so that cell is 6.